Prove the following two properties of the Huffman encoding scheme. (a) If some character occurs with frequency more than 2 / 5, then there is guaranteed to be a codeword of length 1. (b) If all characters occur with frequency less than 1 / 3, then there is guaranteed to be no codeword of length 1 . | Numerade

[GET ANSWER] what generalization can you make about huffman encoding versus run through or keyword encoding how resilient are these methods to errors which would probably arise as the bits flow through a 43491

Huffman-Codierung | einfach erklärt